SQLite 左外连接 LEFT OUT JOIN

SQLite 中的左外连接首先获取第一张表所有记录,然后将第二张表中匹配的数据放到一起,第二张表中没有匹配的数据则抛弃

语法

SQLite 中的左外连接 ( LEFT OUT JOIN ) 语法如下

例如下面的语句可以将 tbl_languagetbl_rank 两个表做一个左外连接

SELECT tbl_language.id,tbl_language.name,tbl_rank.rank 
FROM tbl_language 
LEFT OUTER JOIN tbl_rank on tbl_language.name = tbl_rank.name;

范例

先运行下面的 SQL 语句创建测试数据

DROP TABLE IF EXISTS `tbl_language`;
DROP TABLE IF EXISTS `tbl_rank`;

CREATE TABLE IF NOT EXISTS `tbl_language`(
   `id` INT UNSIGNED AUTO_INCREMENT,
   `name` VARCHAR(64) NOT NULL,
   `url` VARCHAR(128) NOT NULL,
   `founded_at` DATE,
   PRIMARY KEY ( `id` )
);

CREATE TABLE IF NOT EXISTS `tbl_rank`(
   `id` INT UNSIGNED AUTO_INCREMENT,
   `name` VARCHAR(64) NOT NULL,
   `month` VARCHAR(7) NOT NULL,
   `rank` TINYINT NOT NULL,
   `rate` VARCHAR(32) NOT NULL,
   PRIMARY KEY ( `id` )
);

INSERT INTO `tbl_language` VALUES
    (1,'Python','https://www.twle.cn','1991-2-20'),
    (2,'PHP','http://www.php.net','1994-1-1'),
    (3,'Ruby','https://www.ruby-lang.org/','1996-12-25'),
    (4,'Kotlin','http://kotlinlang.org/','2016-02-17');;

INSERT INTO `tbl_rank` VALUES
    (1, 'Python','2018-04',4,'5.083%'),
    (2, 'PHP','2018-04',6,'4.218%'),
    (3, 'Ruby','2018-04',11,'2.018%'),
    (4, 'Java','2018-04',1,'15.777%'),
    (5, 'Python','2018-03',4,'5.869%'),
    (6, 'PHP','2018-03',7,'4.010%'),
    (7, 'Ruby','2018-03',12,'2.744%'),
    (8, 'Java','2018-03',1,'14.941'),
    (9, 'Python','2018-02',4,'5.168%'),
    (10, 'PHP','2018-02',7,'3.420%'),
    (11, 'Ruby','2018-02',10,'2.534%'),
    (12, 'Java','2018-02',1,'14.988%');

tbl_language 表中的数据如下

+----+--------+----------------------------+------------+
| id | name   | url                        | founded_at |
+----+--------+----------------------------+------------+
|  1 | Python | https://www.twle.cn        | 1991-02-20 |
|  2 | PHP    | http://www.php.net         | 1994-01-01 |
|  3 | Ruby   | https://www.ruby-lang.org/ | 1996-12-25 |
|  4 | Scala  | http://kotlinlang.org/     | 2016-02-17 |
+----+--------+----------------------------+------------+

tbl_rank 表中的数据如下

+----+--------+---------+------+---------+
| id | name   | month   | rank | rate    |
+----+--------+---------+------+---------+
|  1 | Python | 2018-04 |    4 | 5.083%  |
|  2 | PHP    | 2018-04 |    6 | 4.218%  |
|  3 | Ruby   | 2018-04 |   11 | 2.018%  |
|  4 | Java   | 2018-04 |    1 | 15.777% |
|  5 | Python | 2018-03 |    4 | 5.869%  |
|  6 | PHP    | 2018-03 |    7 | 4.010%  |
|  7 | Ruby   | 2018-03 |   12 | 2.744%  |
|  8 | Java   | 2018-03 |    1 | 14.941  |
|  9 | Python | 2018-02 |    4 | 5.168%  |
| 10 | PHP    | 2018-02 |    7 | 3.420%  |
| 11 | Ruby   | 2018-02 |   10 | 2.534%  |
| 12 | Java   | 2018-02 |    1 | 14.988% |
+----+--------+---------+------+---------+

然后使用下面的语句创建一个左外连接

SELECT tbl_language.id,tbl_language.name,tbl_rank.rank 
FROM tbl_language 
LEFT OUTER JOIN tbl_rank on tbl_language.name = tbl_rank.name;

输出结果如下

id          name        rank      
----------  ----------  ----------
1           Python      4         
1           Python      4         
1           Python      4         
2           PHP         6         
2           PHP         7         
2           PHP         7         
3           Ruby        10        
3           Ruby        11        
3           Ruby        12        
4           Kotlin   

SQLite 基础教程

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